Log in to get rid of this advertisement Hello all, I need to convert an integer to a decimal to compare it to another decimal value for later use. In the above expression, the product of b and c is calculated first and finally the addition and subtraction follow.Īs I mentioned previously, anything you do between $((.)) is considered to be an arithmetic operation. Rep: bash scripting: converting integer to decimal. It is same as how I had defined a and b earlier.
Let's use a third variable d for another operation: d=10Īll these implicit declarations are still strings. The -n option tells sort to interpret the first word on each line as a number (instead of as a character string) the -r tells it to reverse the comparisons.
To make the addition successful, you need to “convert” it through an arithmetic expansion: echo $cĭo note that c is still actually a string, until you implicitly use the same arithmetic expansion again for another operation that I'll discuss in a while. Let's now try to add both numbers and store the value in a third variable c: echo $cĪs you can see on the output above, c is also being treated as a string. not convert an string to a number on numerical comparisons: sh -c 2+2 -eq. Code: print 'Numeric', '23' + 0 -> 23 is Numeric.
#Bash convert string to integer for comparison how to#
You can check the assigned number: echo echo $b How to compare two strings in variables in bash. One of the approaches I found so fare was to simply add a numeric value and thereby convert it. Let's declare some "numbers" which are basically strings of characters. For numerical comparison, the fromJSON() function can be used to convert a. Let's see the conversion of strings into numbers in a bit more detail so that you can use arithmetic calculations in bash. As part of an expression, you can use boolean, null, number, or string. Anything you do inside $((.)) is considered to be arithmetic operation.
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